1. Find the 75th percentile of units sold across all orders
| Order ID | Region | Rep | Units | Unit Price | Order Date |
| 1001 | North | Alice | 5 | 120 | 2024-01-05 |
| 1002 | South | Bob | 3 | 150 | 2024-01-08 |
| 1003 | East | Carol | 8 | 95 | 2024-01-10 |
| 1004 | West | Dave | 2 | 200 | 2024-01-12 |
| 1005 | North | Alice | 6 | 130 | 2024-01-15 |
| 1006 | South | Bob | 4 | 160 | 2024-01-18 |
| 1007 | East | Carol | 7 | 105 | 2024-01-20 |
| 1008 | West | Dave | 9 | 110 | 2024-01-22 |
=PERCENTILE.EXC(B2:B9, 0.75)
Result: 7.75
The Units column contains [5, 3, 8, 2, 6, 4, 7, 9]. When sorted, these become [2, 3, 4, 5, 6, 7, 8, 9]. PERCENTILE.EXC calculates position 0.75 × (8+1) = 6.75, interpolating between the 6th and 7th values (7 and 8), yielding 7.75. This represents the 75th percentile of order volumes.
2. Find the 25th percentile of unit prices to identify budget products
| Order ID | Region | Rep | Units | Unit Price | Order Date |
| 1001 | North | Alice | 5 | 120 | 2024-01-05 |
| 1002 | South | Bob | 3 | 150 | 2024-01-08 |
| 1003 | East | Carol | 8 | 95 | 2024-01-10 |
| 1004 | West | Dave | 2 | 200 | 2024-01-12 |
| 1005 | North | Alice | 6 | 130 | 2024-01-15 |
| 1006 | South | Bob | 4 | 160 | 2024-01-18 |
| 1007 | East | Carol | 7 | 105 | 2024-01-20 |
| 1008 | West | Dave | 9 | 110 | 2024-01-22 |
=PERCENTILE.EXC(E2:E9, 0.25)
Result: 106.25
Unit prices [120, 150, 95, 200, 130, 160, 105, 110] sort to [95, 105, 110, 120, 130, 150, 160, 200]. Position 0.25 × 9 = 2.25 falls between the 2nd value (105) and 3rd value (110). Linear interpolation: 105 + 0.25 × (110 − 105) = 106.25, marking the threshold where the cheapest 25% of products end.
3. Calculate the median revenue per order
| Order ID | Region | Rep | Units | Unit Price | Revenue |
| 1001 | North | Alice | 5 | 120 | 600 |
| 1002 | South | Bob | 3 | 150 | 450 |
| 1003 | East | Carol | 8 | 95 | 760 |
| 1004 | West | Dave | 2 | 200 | 400 |
| 1005 | North | Alice | 6 | 130 | 780 |
| 1006 | South | Bob | 4 | 160 | 640 |
| 1007 | East | Carol | 7 | 105 | 735 |
| 1008 | West | Dave | 9 | 110 | 990 |
=PERCENTILE.EXC(I2:I9, 0.5)
Result: 687.5
Revenue totals [600, 450, 760, 400, 780, 640, 735, 990] sort to [400, 450, 600, 640, 735, 760, 780, 990]. The median (50th percentile) uses position 0.5 × 9 = 4.5, landing between the 4th value (640) and 5th value (735). Interpolation: 640 + 0.5 × (735 − 640) = 687.5, representing the true middle of the revenue distribution.